Question

e the relationship you determined to w view solution history try again are you getting ahead of yoursel yet. multiply both sides :multiply both sides by what? 6x( 1 ) = 120( )

Explanation:

Step1: Identify the equation structure

We have an equation involving \(6x\) and \(120\). To solve for \(x\), we need to isolate \(x\). If the original equation is \(6x = 120\) (or a similar form where we need to multiply both sides by the reciprocal or a value to solve for \(x\)), but looking at the form \(6x(\quad)=120(\quad)\), we assume we want to solve for \(x\), so we multiply both sides by \(\frac{1}{6}\) (or divide by 6) to isolate \(x\). So we multiply both sides by \(\frac{1}{6}\).

Step2: Fill in the blanks

For the left - hand side, we multiply \(6x\) by \(\frac{1}{6}\), and for the right - hand side, we multiply \(120\) by \(\frac{1}{6}\) (or we can think of it as dividing both sides by 6, which is equivalent to multiplying by \(\frac{1}{6}\)).

Answer:

The first blank (next to \(6x\)) and the second blank (next to \(120\)) should both be filled with \(\frac{1}{6}\) (or \(6\) if we were doing the inverse operation in a different context, but in the context of solving \(6x = 120\) for \(x\), we use \(\frac{1}{6}\)). So \(6x\times\frac{1}{6}=120\times\frac{1}{6}\), which simplifies to \(x = 20\). So the values to fill in the blanks are \(\frac{1}{6}\) (for both blanks).