QUESTION IMAGE
Question
the relative frequency table shows the results of a survey in which parents were asked how much time their children spend playing outside and how much time they spend using electronics.
time spent by children
| at least 1 hr/day using electronics | less than 1 hr/day using electronics | total | |
|---|---|---|---|
| less than 1 hr/day outside | 42 | 6 | 48 |
| total | 44 | 20 | 64 |
given that a child spends at least 1 hour per day outside, what is the probability, rounded to the nearest hundredth if necessary, that the child spends less than 1 hour per day on electronics?
○ 0.22
○ 0.25
○ 0.70
○ 0.88
Step1: Identify conditional probability set
We focus on children who spend at least 1 hr/day outside. The total number of such children is 16, and the number of these children who spend less than 1 hr/day on electronics is 14.
Step2: Calculate conditional probability
Conditional probability formula: $P(A|B)=\frac{\text{Number of } A \cap B}{\text{Number of } B}$
Substitute values: $\frac{14}{16}$
Step3: Simplify and round
$\frac{14}{16}=0.875$, rounded to nearest hundredth is $0.88$.
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0.88