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repeated challenges solve as many inequalities as you have time for to …

Question

repeated challenges
solve as many inequalities as you have time for to help shira eat all the grass.
$8 \geq 3x - 13$

Explanation:

Step1: Add 13 to both sides

To isolate the term with \( x \), we add 13 to both sides of the inequality \( 8 \geq 3x - 13 \). This gives us \( 8 + 13 \geq 3x - 13 + 13 \), which simplifies to \( 21 \geq 3x \).

Step2: Divide both sides by 3

Now, we divide both sides of the inequality \( 21 \geq 3x \) by 3 to solve for \( x \). So, \( \frac{21}{3} \geq \frac{3x}{3} \), which simplifies to \( 7 \geq x \) or \( x \leq 7 \).

Answer:

\( x \leq 7 \)