Question

required information .
a 75-kg woman in an elevator is accelerating upward at a rate of 1.1 $m/s^2$.
note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part.
what is the normal force pushing upward on the womans feet? (note: a picture of the forces on her will help.)
the normal force pushing upward on the womans feet is n.

Explanation:

Step1: List given values

Mass $m=75\ \text{kg}$, upward acceleration $a=1.1\ \text{m/s}^2$, gravitational acceleration $g=9.8\ \text{m/s}^2$

Step2: Apply Newton's 2nd Law

For upward acceleration, net force: $F_N - mg = ma$
Rearrange to solve for normal force: $F_N = m(g+a)$

Step3: Substitute values

$F_N = 75\ \text{kg} \times (9.8\ \text{m/s}^2 + 1.1\ \text{m/s}^2) = 75 \times 10.9$

Answer:

817.5