Question

review: match up graphs 1 - 4 with the correct description of the motion of the object for section one, and then use the section two graph to complete questions 5 - 7. graph 5 1. 1 object is staying in the same place. 2. 2 object is moving at a constant velocity 3. 4 object is accelerating. 4. 3 object is moving at a constant velocity and then stops/stays in the same place. 5. c which section(s) of the graph show(s) an object accelerating? a) a b) b c) c d) a and c 6. a which section(s) of the graph show(s) an object moving at a constant velocity? a) a b) b c) c d) a and c 5. which section(s) of the graph show(s) an object accelerating at a rate of about 2 m/s²? a) a b) b c) c d) a and c

Explanation:

Step1: Recall velocity - time graph concepts

On a velocity - time graph, acceleration is the slope of the graph. Constant velocity means zero acceleration (horizontal line), and acceleration means non - zero slope.

Step2: Analyze section A

In section A of the velocity - time graph, the velocity is increasing at a constant rate. The slope of the line in section A is non - zero and constant. We can calculate the slope using the formula $a=\frac{\Delta v}{\Delta t}$. If we assume the initial velocity $v_1 = 0$ at $t_1=0$ and final velocity $v_2 = 40$ m/s at $t_2 = 20$ s, then $a=\frac{40 - 0}{20-0}=2$ m/s².

Step3: Analyze section B

In section B, the velocity is constant (horizontal line), so the acceleration is $a = 0$ m/s².

Step4: Analyze section C

In section C, the velocity is increasing again, so there is non - zero acceleration.

Answer:

1. d) A and C
2. b) B
3. a) A