QUESTION IMAGE
Question
rewrite without parentheses.
$-6v^{2}(-3v^{3}+4v^{2}+6)$
simplify your answer as much as possible.
Step1: Distribute -6v²
Multiply -6v² with each term inside the parentheses:
$-6v^2 \times (-3v^3) + (-6v^2) \times 4v^2 + (-6v^2) \times 6$
Step2: Simplify each product
- For the first term: $(-6) \times (-3) = 18$, $v^2 \times v^3 = v^{2 + 3} = v^5$, so $18v^5$.
- For the second term: $(-6) \times 4 = -24$, $v^2 \times v^2 = v^{2 + 2} = v^4$, so $-24v^4$.
- For the third term: $(-6) \times 6 = -36$, so $-36v^2$.
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$18v^5 - 24v^4 - 36v^2$