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1. rich added 26.2 milliliters of water to a solution in science class.…

Question

  1. rich added 26.2 milliliters of water to a solution in science class. the directions said to add 22.6 milliliters of water. what was the percent error (to the nearest hundredth percent) in the amount of water rich added?

a 13.74%
b 15.93%
c 16.79%
d 19.47%

  1. a worker fills a 15,000 - gallon swimming pool at a rate of 50 gallons per minute. how many minutes will it take for the pool to be filled halfway?

record your answer in the boxes. then fill in the bubbles. be sure to use the correct place value.

  1. jessica started spending more time on her math homework, and as a result her average grade increased from an 82 to an 88 over a 3 - week period. to the nearest tenth of a percent, what was the percent increase in her average grade over the 3 - week period?

a 93.1%
b 7.3%
c 6.8%
d 6.0%

  1. uri wants to buy a sweatshirt that costs $16.28. if the tax is 8%, about how much will uri need to buy the sweatshirt?

a $13.02
b $16.36
c $17.58
d $29.30

Explanation:

Step1: Calculate absolute error

$\text{Absolute Error} = |26.2 - 22.6| = 3.6$

Step2: Compute percent error

$\text{Percent Error} = \frac{3.6}{22.6} \times 100\% \approx 15.93\%$

Step1: Find half the pool volume

$\text{Half Volume} = \frac{15000}{2} = 7500$ gallons

Step2: Calculate fill time

$\text{Time} = \frac{7500}{50} = 150$ minutes

Step1: Find grade difference

$\text{Difference} = 88 - 82 = 6$

Step2: Compute percent increase

$\text{Percent Increase} = \frac{6}{82} \times 100\% \approx 7.3\%$

Step1: Calculate tax amount

$\text{Tax} = 16.28 \times 0.08 = 1.3024$

Step2: Find total cost

$\text{Total Cost} = 16.28 + 1.3024 \approx 17.58$

Answer:

B 15.93%

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