QUESTION IMAGE
Question
in a right triangle with angle θ, sinθ = 4/5 and the hypotenuse is 20 cm. what is the length of one of the non - hypotenuse legs?
Step1: Recall sine definition
$\sin\theta = \frac{\text{opposite leg}}{\text{hypotenuse}}$
Step2: Plug in known values
$\frac{4}{5} = \frac{\text{opposite leg}}{20}$
Step3: Solve for the leg
$\text{opposite leg} = \frac{4}{5} \times 20$
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16 cm