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in right - triangle jkl, jk = 13 yd, kl = 17 yd. jl = ____

Question

in right - triangle jkl, jk = 13 yd, kl = 17 yd. jl = ____

Explanation:

Step1: Identify the theorem

Since it's a right - triangle, use the Pythagorean theorem \(a^{2}+b^{2}=c^{2}\), where \(c\) is the hypotenuse and \(a\) and \(b\) are the legs. Here, \(a = 13\) and \(b = 17\), and we want to find the hypotenuse \(JL\) (let \(JL=c\)).

Step2: Apply the Pythagorean theorem

\(c=\sqrt{13^{2}+17^{2}}=\sqrt{169 + 289}=\sqrt{458}\approx21.4\) yd

Answer:

\(\sqrt{458}\approx21.4\) yd