Question

rosa owns two dogs and monitors how much food they eat in a month. dog food consumption chance 60% ace 40% if a total of 20 kilograms of food were eaten, how much more was eaten by chance than by ace? kilograms

Explanation:

Step1: Find food eaten by Chance

Total food is 20 kg, Chance eats 60%. So, $20\times0.6 = 12$ kg.

Step2: Find food eaten by Ace

Ace eats 40% of 20 kg. So, $20\times0.4 = 8$ kg.

Step3: Find the difference

Subtract Ace's food from Chance's: $12 - 8 = 4$ kg.

Answer:

4