Question

rotate △bhs counterclockwise 90° about the origin. label your rotation △bhs. b(0,4) h(3,-1) s(6,5)

Explanation:

Step1: Recall rotation rule

The rule for rotating a point $(x,y)$ counter - clockwise 90° about the origin is $(x,y)\to(-y,x)$.

Step2: Rotate point B

For $B(0,4)$, using the rule $(-y,x)$, we have $B'( - 4,0)$.

Step3: Rotate point H

For $H(3,-1)$, using the rule $(-y,x)$, we get $H'(1,3)$.

Step4: Rotate point S

For $S(6,5)$, using the rule $(-y,x)$, we obtain $S'(-5,6)$.

Answer:

$B'(-4,0),H'(1,3),S'(-5,6)$