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rotation 90° counterclockwise about the origin #7: graph r_(90°,0)(△fgh…

Question

rotation 90° counterclockwise about the origin #7: graph r_(90°,0)(△fgh).

Explanation:

Step1: Recall rotation rule

The rule for a 90 - degree counter - clockwise rotation about the origin is $(x,y)\to(-y,x)$.

Step2: Identify vertices

Let the coordinates of the vertices of $\triangle FGH$ be $F(x_1,y_1)$, $G(x_2,y_2)$, and $H(x_3,y_3)$.

Step3: Apply rotation rule

The new coordinates of $F$ will be $F'(-y_1,x_1)$, of $G$ will be $G'(-y_2,x_2)$, and of $H$ will be $H'(-y_3,x_3)$.

Step4: Plot new triangle

Plot the points $F'$, $G'$, and $H'$ and connect them to form $\triangle F'G'H'$.

Answer:

Graph the new triangle $\triangle F'G'H'$ with vertices obtained by applying the 90 - degree counter - clockwise rotation rule $(x,y)\to(-y,x)$ to the vertices of $\triangle FGH$.