Question

round 2 - adding fractions

1. $-\frac{2}{3} + \frac{1}{3} =$
2. $\frac{5}{6} + (-\frac{1}{6}) =$

Explanation:

Problem 1: $-\frac{2}{3} + \frac{1}{3}$

Step 1: Add the numerators (same denominator)

Since the denominators are the same ($3$), we add the numerators: $-2 + 1 = -1$.

Step 2: Keep the denominator

The denominator remains $3$, so the result is $\frac{-1}{3}=-\frac{1}{3}$.

Step 1: Add the numerators (same denominator)

The denominators are the same ($6$), so add the numerators: $5 + (-1) = 4$.

Step 2: Keep the denominator

The denominator remains $6$, so the result is $\frac{4}{6}$, which simplifies to $\frac{2}{3}$ (dividing numerator and denominator by $2$).

Answer:

$-\frac{1}{3}$

Problem 3: $\frac{5}{6} + (-\frac{1}{6})$