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Question
in round numbers of daltons, sucrose has a molecular mass of daltons. because we can’t weigh out small numbers of molecules, we usually measure substances in units called moles. just as a dozen always means 12 objects, a mole (mol) represents an exact number of objects: which is called avogadro’s number. because of the way in which avogadro’s number and the unit dalton were originally defined, once we determine the molecular mass of a molecule such as sucrose, we can use the same number, but with the unit gram, to represent the mass of molecules of sucrose, or 1 mol of sucrose (sometimes called the molar mass). (for example, o has a mass of 16. therefore, one mole of o has a mass of 16 x 11 = 176 g/mole.)
c. add the masses of each element in the molecule to get the molar mass of sucrose.
to obtain 1 mol of sucrose in the lab, therefore, we weigh out _ g.
how would we make a liter (l) of solution consisting of 1 mol of sucrose dissolved in water? we would measure out _ g of sucrose and then gradually add water, while stirring, until the sugar was completely dissolved. we would then add enough water to bring the total volume of the solution up to 1 l. at that point, we would have a 1 - molar (1 m) solution of sucrose.
Step1: Recall the chemical formula of sucrose
The chemical formula of sucrose is $C_{12}H_{22}O_{11}$.
Step2: Determine the atomic masses of elements
The atomic mass of carbon (C) is approximately 12 g/mol, hydrogen (H) is approximately 1 g/mol, and oxygen (O) is approximately 16 g/mol.
Step3: Calculate the molar - mass of sucrose
For carbon in sucrose: $12\times12 = 144$ g/mol (12 carbon atoms with atomic mass 12 g/mol each).
For hydrogen in sucrose: $1\times22=22$ g/mol (22 hydrogen atoms with atomic mass 1 g/mol each).
For oxygen in sucrose: $16\times11 = 176$ g/mol (11 oxygen atoms with atomic mass 16 g/mol each).
The molar - mass of sucrose $M$ is the sum of the masses of each element: $M=144 + 22+176=342$ g/mol.
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