Question

sam finds a gold - colored rock on a hike. he researches to find the density of gold is 19.3 g/cm³. sam uses a graduated cylinder and water displacement to find the volume of the rock to be 3.5 cm³. if the rock were gold, what would be the mass? a. 5.5 grams b. 16 grams c. 23 grams d. 68 grams

Explanation:

Step1: Recall density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume. We want to find $m$, and we know $
ho = 19.3\ g/cm^{3}$ and $V=3.5\ cm^{3}$. Rearranging the formula for $m$ gives $m =
ho\times V$.

Step2: Substitute values

Substitute $
ho = 19.3\ g/cm^{3}$ and $V = 3.5\ cm^{3}$ into the formula $m=
ho\times V$. So $m=19.3\times3.5$.
$m = 67.55\approx68$ grams (rounding to the nearest whole - number).

Answer:

D. 68 grams