Question

sam pushes a box to the left with 15 n. sally and juan push to the right with 5 n each. what is the net force on the box? 5 n 5 n 15 n 10 n right 5 n left 15 n left 1 n left

Explanation:

Step1: Calculate right - hand forces sum

The forces to the right are applied by Sally and Juan. Each applies 5 N, so the sum of right - hand forces $F_{right}=5 + 5=10$ N.

Step2: Calculate the net force

Let the left - hand force be $F_{left}=15$ N. The net force $F_{net}=F_{left}-F_{right}$. Substitute the values: $F_{net}=15 - 10 = 5$ N. Since $F_{left}>F_{right}$, the direction of the net force is to the left.

Answer:

5 N left