Question

samuel is pushing a shopping cart toward his car at 2 meters per second. he is 96 meters away from his car. if his velocity remains constant, how much time will it take him to move one - third of the way to his car? write your answer as a whole number. seconds

Explanation:

Step1: Calculate one - third of the distance

One - third of 96 meters is $\frac{1}{3}\times96 = 32$ meters.

Step2: Use the formula $t=\frac{d}{v}$

We know velocity $v = 2$ m/s and distance $d = 32$ m. Substituting into the formula $t=\frac{d}{v}$, we get $t=\frac{32}{2}=16$ s.

Answer:

16