Question

1. for a school fundraiser, mai will make school spirit bracelets. she will order bead wiring and alphabet beads to create the school name on the bracelets. mai must spend $250 on wire and $5.30 per bracelet for beads.

a. complete the table giving the total cost mai will spend to make each specific number of bracelets.

number of bracelets	cost in dollars
40
60

b. write an expression for the cost of making $n$ bracelets.
c. what is the maximum number of bracelets mai can make with a budget of $1,500?

Explanation:

Step1: Define cost formula

Total cost = Fixed wire cost + (Cost per bracelet × Number of bracelets), or $C = 250 + 5.30n$

Step2: Calculate cost for 20 bracelets

Substitute $n=20$ into the formula:
$C = 250 + 5.30\times20 = 250 + 106 = 356$

Step3: Calculate cost for 40 bracelets

Substitute $n=40$ into the formula:
$C = 250 + 5.30\times40 = 250 + 212 = 462$

Step4: Calculate cost for 60 bracelets

Substitute $n=60$ into the formula:
$C = 250 + 5.30\times60 = 250 + 318 = 568$

Step5: Write general cost expression

Use fixed cost + variable cost per bracelet:
$C = 250 + 5.30n$

Step6: Solve for max bracelets with $1500$

Set up inequality $250 + 5.30n \leq 1500$, isolate $n$:
$5.30n \leq 1500 - 250$
$5.30n \leq 1250$
$n \leq \frac{1250}{5.30} \approx 235.85$
Round down to whole number.

Answer:

a.

number of bracelets	cost in dollars
40	462
60	568

b. $250 + 5.30n$

c. 235