Question

at the school olympics, the 6 teams ended with the following point totals: 28 points 94 points 10 points 13 points 58 points 91 points. what was the mean absolute deviation of the point totals? if the answer is a decimal, round it to the nearest tenth. mean absolute deviation (mad): points

Explanation:

Step1: Calculate the mean

The mean $\bar{x}=\frac{28 + 94+10+13+58+91}{6}=\frac{294}{6}=49$

Step2: Calculate the absolute deviations

$|28 - 49|=21$, $|94 - 49| = 45$, $|10 - 49|=39$, $|13 - 49| = 36$, $|58 - 49|=9$, $|91 - 49| = 42$

Step3: Calculate the mean of absolute deviations

$MAD=\frac{21+45+39+36+9+42}{6}=\frac{192}{6}=32$

Answer:

32