Question

a scientist makes an acid solution by adding drops of acid to 1.2 l of water. the final volume of the acid solution is 1.202 l. assuming the volume of each drop is 0.05 ml, how many drops were added to the water? about what percent of the acid solution is acid?
find the number of drops of acid that were added to the solution.
40 (simplify your answer.)
about % of the solution is the acid.
(round to the nearest hundredth as needed.)

Explanation:

Step1: Calculate volume of added acid

First, convert volumes to the same unit (mL). Initial water volume $V_{water}=1.2\ L = 1.2\times1000 = 1200\ mL$, final solution volume $V_{final}=1.202\ L=1.202\times 1000 = 1202\ mL$. Volume of added acid $V_{acid}=V_{final}-V_{water}=1202 - 1200=2\ mL$.

Step2: Calculate number of drops

Given volume of each drop $v = 0.05\ mL$. Number of drops $n=\frac{V_{acid}}{v}=\frac{2}{0.05}=40$.

Step3: Calculate percentage of acid in solution

Percentage of acid $p=\frac{V_{acid}}{V_{final}}\times 100=\frac{2}{1202}\times 100\approx 0.17\%$.

Answer:

40 drops were added. About $0.17\%$ of the solution is acid.