Question

score on last try: 0 of 1 pt. see details for more. get a similar question you can retry this question below identify which of the given points are solutions to the following linear equations. 2x - 2y = -2 (-2,-2) (-2,-1) (1, 4/3) (2,3)

Explanation:

Step1: Test point (-2,-2)

Substitute $x=-2, y=-2$ into $2x-2y=-2$:
$2(-2) - 2(-2) = -4 + 4 = 0
eq -2$

Step2: Test point (-2,-1)

Substitute $x=-2, y=-1$ into $2x-2y=-2$:
$2(-2) - 2(-1) = -4 + 2 = -2$

Step3: Test point $(1,\frac{4}{3})$

Substitute $x=1, y=\frac{4}{3}$ into $2x-2y=-2$:
$2(1) - 2(\frac{4}{3}) = 2 - \frac{8}{3} = -\frac{2}{3}
eq -2$

Step4: Test point (2,3)

Substitute $x=2, y=3$ into $2x-2y=-2$:
$2(2) - 2(3) = 4 - 6 = -2$

Answer:

(-2,-1), (2,3)