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Question
in 8 seconds, a car goes from traveling at 29 m/s to 21 m/s. what is the acceleration of the car? a = ? $\frac{m}{s^{2}}$ enter the sign (+ or -) and the magnitude. remember: a = $\frac{delta v}{t}$
Step1: Calculate the change in velocity
$\Delta v=v_f - v_i=21 - 29=- 8$ m/s
Step2: Use the acceleration formula
$a=\frac{\Delta v}{t}=\frac{-8}{8}=-1$ m/s²
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-1 m/s²