Question

section 5.2 homework
score: 0/15 answered: 0/15
question 1
a bag of m&ms has 5 red, 4 green, 3 blue, and 2 yellow m&ms. what is the probability of randomly picking: (round to 4 decimal places)
a) a yellow?
b) a blue or green?
c) a red or blue or yellow?

Explanation:

Step1: Calculate total number of M&M's

$5 + 4+3 + 2=14$

Step2: Calculate probability of picking a yellow

The number of yellow M&M's is 2. Probability formula is $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So $P(\text{yellow})=\frac{2}{14}\approx0.1429$

Step3: Calculate number of blue or green M&M's

Number of blue is 3 and green is 4. So number of blue or green is $3 + 4 = 7$. Then $P(\text{blue or green})=\frac{7}{14}= 0.5000$

Step4: Calculate number of red or blue or yellow M&M's

Number of red is 5, blue is 3 and yellow is 2. So number of red or blue or yellow is $5+3 + 2=10$. Then $P(\text{red or blue or yellow})=\frac{10}{14}\approx0.7143$

Answer:

a) $0.1429$
b) $0.5000$
c) $0.7143$