Question

section 2 properties of matter continued
density versus weight
both of these objects have the same volume, but the brick has a larger mass. therefore, the density of the brick is greater than the density of the sponge.
because many dense materials feel heavy, people sometimes confuse density and weight. however, density and weight are not the same thing.
critical thinking

1. apply concepts if the brick and sponge had the same mass, which one would have a greater volume?

how can physical properties affect the use of substances?
determining uses
people often choose a material for a particular use because of its physical properties. for example, helium gas is often used to fill balloons. the density of helium is lower than the density of air. as a result, a balloon filled with helium can float in the sky.
people choose to use some substances because of their ability to conduct electricity. for example, metals are good conductors of electricity. thus, metals such as copper are used in power lines and electric motors.
sometimes people need a substance that does not conduct electricity or heat. for example, plastic foam does not conduct heat well. thus, plastic foam can be used to make cups for hot liquids.
talk about it
describe choose an object in your classroom. identify and describe to the class some of the physical properties of the whole object. also, identify and describe the substances it is made of. explain why you think the particular substances are useful for the object.

Explanation:

Explicación:

Paso 1: Recordar la fórmula de densidad

La densidad ($
ho$) está dada por $
ho=\frac{m}{V}$, donde $m$ es la masa y $V$ es el volumen. Re - arreglando la fórmula, tenemos $V = \frac{m}{
ho}$.

Paso 2: Analizar el caso de igual masa

Si la masa $m$ es la misma para la ladrillo y la esponja, y sabemos que la densidad de la esponja es menor que la densidad del ladrillo ($
ho_{esponja}<
ho_{ladrillo}$). Al aplicar la fórmula $V=\frac{m}{
ho}$, cuando $m$ es constante, una densidad menor implica un volumen mayor. Entonces, la esponja tendrá un volumen mayor.

Respuesta:

La esponja tendría un mayor volumen.

Answer:

Explicación:

Paso 1: Recordar la fórmula de densidad

La densidad ($
ho$) está dada por $
ho=\frac{m}{V}$, donde $m$ es la masa y $V$ es el volumen. Re - arreglando la fórmula, tenemos $V = \frac{m}{
ho}$.

Paso 2: Analizar el caso de igual masa

Si la masa $m$ es la misma para la ladrillo y la esponja, y sabemos que la densidad de la esponja es menor que la densidad del ladrillo ($
ho_{esponja}<
ho_{ladrillo}$). Al aplicar la fórmula $V=\frac{m}{
ho}$, cuando $m$ es constante, una densidad menor implica un volumen mayor. Entonces, la esponja tendrá un volumen mayor.

Respuesta:

La esponja tendría un mayor volumen.