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select all the correct answers. the electron configurations of some ele…

Question

select all the correct answers. the electron configurations of some elements are given. based on the electron configurations, which elements can likely form ions with multiple charges?
□ zinc ar 3d¹⁰ 4s²
□ iron ar 3d⁶ 4s²
□ sodium ne 3s¹
□ cobalt ar 3d⁷ 4s²
□ silver kr 4d¹⁰ 5s¹

Explanation:

Brief Explanations

To determine which elements can form ions with multiple charges, we analyze their electron configurations, focusing on transition metals (with partially filled d - orbitals) as they can lose electrons from both the d - orbitals and s - orbitals.

  1. Zinc ([Ar] \(3d^{10}4s^{2}\)):
  • The \(3d\) orbital is completely filled. Zinc typically loses the 2 electrons from the \(4s\) orbital to form a \(Zn^{2 + }\) ion. It does not have multiple stable oxidation states from losing d - electrons since the d - orbital is full, so it usually forms ions with a single charge ( + 2).
  1. Iron ([Ar] \(3d^{6}4s^{2}\)):
  • Iron is a transition metal with a partially filled \(3d\) orbital. It can lose 2 electrons from the \(4s\) orbital to form \(Fe^{2+}\) and can also lose one more electron from the \(3d\) orbital to form \(Fe^{3+}\). So, iron can form ions with multiple charges.
  1. Sodium ([Ne] \(3s^{1}\)):
  • Sodium is an alkali metal. It has only one valence electron in the \(3s\) orbital. It readily loses this one electron to form a \(Na^{+}\) ion and does not form ions with multiple charges.
  1. Cobalt ([Ar] \(3d^{7}4s^{2}\)):
  • Cobalt is a transition metal with a partially filled \(3d\) orbital. It can lose 2 electrons from the \(4s\) orbital to form \(Co^{2+}\) and can also lose more electrons from the \(3d\) orbital to form \(Co^{3+}\) (and other higher oxidation states in some compounds). So, cobalt can form ions with multiple charges.
  1. Silver ([Kr] \(4d^{10}5s^{1}\)):
  • The \(4d\) orbital is completely filled. Silver typically loses the 1 electron from the \(5s\) orbital to form \(Ag^{+}\). Although in some rare cases it can form \(Ag^{2+}\), its most common and stable ion is \(Ag^{+}\), so it is not considered to form ions with multiple charges as readily as iron and cobalt.

Answer:

B. Iron [Ar] \(3d^{6}4s^{2}\)
D. cobalt [Ar] \(3d^{7}4s^{2}\)