Question

select the subatomic composition of an iron(iii) ion (fe³⁺) with a mass number of 56. refer to a periodic table. 26 protons, 30 neutrons, 23 electrons 30 protons, 26 neutrons, 23 electrons 26 protons, 30 neutrons, 29 electrons 30 protons, 26 neutrons, 29 electrons

Explanation:

Step1: Determine number of protons

Iron (Fe) has an atomic number of 26. Atomic number = number of protons, so number of protons = 26.

Step2: Calculate number of neutrons

Mass number = number of protons + number of neutrons. Given mass - number = 56 and number of protons = 26. So number of neutrons = 56 - 26=30.

Step3: Determine number of electrons

The ion is $Fe^{3 + }$, which means it has lost 3 electrons. A neutral Fe atom has 26 electrons. So number of electrons in $Fe^{3 + }$ = 26 - 3 = 23.

Answer:

26 protons, 30 neutrons, 23 electrons