Question

1. on a separate sheet of paper, write out the problem using all the steps. round using significant figures. how many moles of water are produced when 7.60 moles of propane (c₃h₈) combust in the presence of oxygen? c₃h₈ + o₂ → co₂ + h₂o

Explanation:

For Question 5:

Step1: Balance the given reaction

The reaction $\ce{N2 + 3H2 -> 2NH3}$ is already balanced. The mole ratio of $\ce{N2}$ to $\ce{NH3}$ is $1:2$.

Step2: Calculate moles of $\ce{NH3}$

Use the mole ratio to find the product moles:
$\text{Moles of } \ce{NH3} = 17\ \text{mol } \ce{N2} \times \frac{2\ \text{mol } \ce{NH3}}{1\ \text{mol } \ce{N2}}$

Step1: Balance the combustion reaction

Balance $\ce{C3H8 + O2 -> CO2 + H2O}$:
$\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}$
The mole ratio of $\ce{C3H8}$ to $\ce{H2O}$ is $1:4$.

Step2: Calculate moles of $\ce{H2O}$

Use the mole ratio to find the product moles:
$\text{Moles of } \ce{H2O} = 7.60\ \text{mol } \ce{C3H8} \times \frac{4\ \text{mol } \ce{H2O}}{1\ \text{mol } \ce{C3H8}}$

Answer:

$34\ \text{mol}$

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For Question 6: