Question

	set 1	set 2
mass 1	1,100 kg	1,100 kg
mass 2	1,100 kg	700 kg
distance	11 m	11 m

which set has more gravitational force energy?
remember : $f = \frac{-g(m_1 m_2)}{d^2}$
the sets have an equal amount of gravitational force energy.
set 1
set 2

Explanation:

Step1: Analyze Set 1's Force

For Set 1, \( m_1 = 1100\space kg \), \( m_2 = 1100\space kg \), \( d = 11\space m \).
Using \( F = \frac{-G(m_1m_2)}{d^2} \), substitute values:
\( F_1 = \frac{-G(1100 \times 1100)}{11^2} \)

Step2: Analyze Set 2's Force

For Set 2, \( m_1 = 1100\space kg \), \( m_2 = 700\space kg \), \( d = 11\space m \).
Substitute into the formula:
\( F_2 = \frac{-G(1100 \times 700)}{11^2} \)

Step3: Compare \( F_1 \) and \( F_2 \)

Since \( G \) and \( d^2 \) are the same, compare \( m_1m_2 \):
Set 1: \( 1100 \times 1100 = 1,210,000 \)
Set 2: \( 1100 \times 700 = 770,000 \)
\( 1,210,000 > 770,000 \), so \( |F_1| > |F_2| \). The negative sign indicates direction, so magnitude of \( F_1 \) is larger.

Answer:

Set 1