Question

set w1 = 2.5 kip/ft and w2 = 2 kip/ft (figure 1). determine the magnitude of the equivalent resultant force of the distributed loading. express your answer in kilopounds to three significant figures. part a incorrect; try again; 2 attempts remaining previous answers request answer fr = kip part b

Explanation:

Step1: Calculate force of triangular load

The formula for the magnitude of a triangular - distributed load is $F_{t}=\frac{1}{2}w_{1}l$, where $w_{1}$ is the maximum intensity and $l$ is the length over which it acts. Here, $w_{1} = 2.5$ kip/ft and $l = 4.5$ ft. So, $F_{t}=\frac{1}{2}\times2.5\times4.5=\frac{2.5\times4.5}{2}=5.625$ kip.

Step2: Calculate force of rectangular load

The formula for the magnitude of a rectangular - distributed load is $F_{r}=w_{2}l$, where $w_{2}$ is the intensity and $l$ is the length. Here, $w_{2}=2$ kip/ft and $l = 6$ ft. So, $F_{r}=2\times6 = 12$ kip.

Step3: Calculate resultant force

The resultant force $F_{R}$ of the distributed loading is the sum of the force of the triangular load and the force of the rectangular load. So, $F_{R}=F_{t}+F_{r}=5.625 + 12=17.625\approx17.6$ kip.

Answer:

$17.6$ kip