Question

a seven - sided number cube with sides numbered 1, 2, 3, 4, 5, 6, 7 is rolled. what is the probability that a 4 or an odd number is rolled?
\\(\frac{4}{49})\
\\(\frac{2}{7})\
\\(\frac{3}{7})\
\\(\frac{5}{7})

Explanation:

Step1: Identify odd - numbered sides

The odd - numbered sides of the seven - sided cube are 1, 3, 5, 7. There are 4 odd - numbered sides.

Step2: Consider the number 4

We want to find the probability of rolling a 4 or an odd number. The number 4 is not an odd number.

Step3: Calculate the number of favorable outcomes

The set of favorable outcomes (rolling a 4 or an odd number) has 4 (odd numbers) + 1 (the number 4) = 5 elements.

Step4: Calculate the probability

The probability $P$ of an event is given by the formula $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. The total number of outcomes when rolling the seven - sided cube is 7. So $P = \frac{5}{7}$.

Answer:

$\frac{5}{7}$