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sherry bought 6 items at the school store. the items cost: $2, $4, $1, …

Question

sherry bought 6 items at the school store. the items cost: $2, $4, $1, $4, $2, $2
david also bought 6 items at the school store. the items cost: $7, $5, $0.10, $9, $0.15, $0.50
on average, who spent more at the school store?

Explanation:

Step1: Calculate Sherry's total cost

$2 + 4+1 + 4+2 + 2=15$

Step2: Calculate Sherry's average cost

The average cost is the total cost divided by the number of items. So Sherry's average cost is $\frac{15}{6}=2.5$

Step3: Calculate David's total cost

$7 + 5+0.10 + 9+0.15 + 0.50=21.75$

Step4: Calculate David's average cost

David's average cost is $\frac{21.75}{6}=3.625$

Step5: Compare the average costs

Since $3.625>2.5$, David spent more on average.

Answer:

David