Question

this shows a function.
$f(x)=\

$$\begin{cases}8 & ;x < -6 \\\\5x - x^3;&x\\geq -6\\end{cases}$$

$
what is the value of $f(-1)$?

Explanation:

Step1: Identify relevant function piece

Since $-1 \geq -6$, use $f(x)=5x-x^3$.

Step2: Substitute $x=-1$ into the function

$f(-1)=5(-1)-(-1)^3$

Step3: Calculate each term

$5(-1) = -5$, $(-1)^3 = -1$, so $-(-1)=1$

Step4: Sum the results

$-5 + 1 = -4$

Answer:

$-4$