Question

1. silver has a density of 10.5 g/cm³ and gold has a density of 19.3 g/cm³. which would have a greater mass, 9.65 cm³ of silver of 9.65 cm³ of gold? show your proof

Explanation:

Step1: Calculate mass of silver

Use formula $m =
ho V$, where $
ho$ is density and $V$ is volume. For silver, $
ho_{Ag}=10.5\ g/cm^{3}$ and $V = 9.65\ cm^{3}$. So $m_{Ag}=
ho_{Ag}\times V=10.5\times9.65$.
$m_{Ag}=10.5\times9.65 = 101.325\ g$

Step2: Calculate mass of gold

For gold, $
ho_{Au}=19.3\ g/cm^{3}$ and $V = 9.65\ cm^{3}$. Using $m=
ho V$, we get $m_{Au}=
ho_{Au}\times V=19.3\times9.65$.
$m_{Au}=19.3\times9.65 = 186.245\ g$

Step3: Compare masses

Since $186.245\ g>101.325\ g$, gold has a greater mass.

Answer:

$9.65\ cm^{3}$ of gold has a greater mass.