Question

simplify. (-8)^{\frac{1}{3}}

Explanation:

Step1: Recall exponent rule

$a^{\frac{1}{n}}=\sqrt[n]{a}$
So, $(-8)^{\frac{1}{3}}=\sqrt[3]{-8}$

Step2: Find cube - root

We know that $(-2)\times(-2)\times(-2)=-8$. So, $\sqrt[3]{-8}=-2$

Answer:

$-2$