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Question
- simplify: $(a + 3)^2 LXB0 \bigcirc$ $a^2 + 9 LXB1 \bigcirc$ $a^2 + 9a + 3$
Step1: Expand using square formula
$$(a+3)^2=(a+3)(a+3)$$
Step2: Apply distributive property
$$a(a+3)+3(a+3)=a^2+3a+3a+9$$
Step3: Combine like terms
$$a^2+(3a+3a)+9=a^2+6a+9$$
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$\boldsymbol{a^2 + 6a + 9}$ (the first option)