QUESTION IMAGE
Question
simplify each expression using the exponent rules with positive exponents only.
- $(3a^{3}b^{4})^{3}$
- $(5m^{4}n^{-5})(2m^{-1}n^{6})$
- $6^{-3}6^{7}$
- $\frac{5(x^{5})}{12x^{-3}}$
- $\frac{(4x^{3})(3x^{6})^{2}}{2x^{-2}}$
simplify each expression completely.
- $7\sqrt{45x^{3}}$
- $-2\sqrt{80x^{5}y^{6}}$
- $sqrt{192km^{2}}$
Step1: Apply power of a product rule
$(3a^3b^4)^3 = 3^3 \cdot (a^3)^3 \cdot (b^4)^3$
Step2: Calculate exponents and constants
$3^3=27$, $(a^3)^3=a^{3 \times 3}=a^9$, $(b^4)^3=b^{4 \times 3}=b^{12}$
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Step1: Multiply coefficients, combine like bases
$(5m^4n^{-5})(2m^{-1}n^6) = (5 \times 2) \cdot m^{4+(-1)} \cdot n^{-5+6}$
Step2: Simplify each part
$5 \times 2=10$, $m^{4-1}=m^3$, $n^{-5+6}=n^1=n$
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Step1: Apply product of powers rule
$6^{-3}6^7 = 6^{-3+7}$
Step2: Simplify the exponent
$6^{4}=1296$
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Step1: Rewrite negative exponent as positive
$\frac{5(x^5)}{12x^{-3}} = \frac{5x^5 \cdot x^3}{12}$
Step2: Combine like bases
$\frac{5x^{5+3}}{12} = \frac{5x^8}{12}$
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Step1: Expand the squared term
$\frac{(4x^3)(3x^6)^2}{2x^{-2}} = \frac{(4x^3)(9x^{12})}{2x^{-2}}$
Step2: Multiply numerator terms
$\frac{4 \times 9 \cdot x^{3+12}}{2x^{-2}} = \frac{36x^{15}}{2x^{-2}}$
Step3: Divide coefficients, combine exponents
$\frac{36}{2} \cdot x^{15-(-2)} = 18x^{17}$
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Step1: Factor radicand into perfect squares
$7\sqrt{45x^3} = 7\sqrt{9 \times 5 \times x^2 \times x}$
Step2: Simplify the square root
$7 \times 3x\sqrt{5x} = 21x\sqrt{5x}$
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Step1: Factor radicand into perfect squares
$-2\sqrt{80x^5y^6} = -2\sqrt{16 \times 5 \times x^4 \times x \times y^6}$
Step2: Simplify the square root
$-2 \times 4x^2y^3\sqrt{5x} = -8x^2y^3\sqrt{5x}$
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Step1: Factor radicand into perfect squares
$\sqrt{192km^2} = \sqrt{64 \times 3 \times k \times m^2}$
Step2: Simplify the square root
$8|m|\sqrt{3k}$
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- $27a^9b^{12}$
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- $1296$
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- $-8x^2y^3\sqrt{5x}$
- $8|m|\sqrt{3k}$