Question

simplify. express your answer as a single term, without a denominator. $a^{-1}b^{5}c^{-7} \cdot ab^{9}c^{-1}$

Explanation:

Step1: Combine like bases (a terms)

$a^{-1} \cdot a^{1} = a^{-1+1} = a^{0} = 1$

Step2: Combine like bases (b terms)

$b^{5} \cdot b^{9} = b^{5+9} = b^{14}$

Step3: Combine like bases (c terms)

$c^{-7} \cdot c^{-1} = c^{-7+(-1)} = c^{-8}$

Step4: Multiply all results

$1 \cdot b^{14} \cdot c^{-8} = b^{14}c^{-8}$

Answer:

$b^{14}c^{-8}$