Question

simplify the expression below using order of operations.
$\frac{(-4)^2 + (-6)}{-4 - (-2)} - \frac{2 - (-6)}{-7 + 8}$

Explanation:

Step1: Simplify numerators/denominators

First fraction numerator: $(-4)^2 + (-6) = 16 - 6 = 10$
First fraction denominator: $-4 - (-2) = -4 + 2 = -2$
Second fraction numerator: $2 - (-6) = 2 + 6 = 8$
Second fraction denominator: $-7 + 8 = 1$

Step2: Calculate each fraction

First fraction: $\frac{10}{-2} = -5$
Second fraction: $\frac{8}{1} = 8$

Step3: Subtract the two results

$-5 - 8 = -13$

Answer:

$-13$