Question

simplify the following expression.
$(-6h + 4)^2$
$?h^2 + \square h + \square$

Explanation:

Step1: Recall the formula \((a + b)^2 = a^2 + 2ab + b^2\)

Here, \(a=-6h\) and \(b = 4\).

Step2: Calculate \(a^2\)

\(a^2=(-6h)^2=(-6)^2\times h^2 = 36h^2\)

Step3: Calculate \(2ab\)

\(2ab = 2\times(-6h)\times4=2\times(-24h)=-48h\)

Step4: Calculate \(b^2\)

\(b^2 = 4^2=16\)

Step5: Combine the terms

\((-6h + 4)^2=36h^2-48h + 16\)

Answer:

The coefficient of \(h^2\) is \(36\), the coefficient of \(h\) is \(- 48\) and the constant term is \(16\). So the first box (for \(h^2\) coefficient) is \(36\), the second box (for \(h\) coefficient) is \(-48\) and the third box (constant term) is \(16\). For the first box (the one with green color) the answer is \(36\).