Question

simplify the product.
\sqrt{7x^{9}} \cdot \sqrt{28x^{11}}
\sqrt{7x^{9}} \cdot \sqrt{28x^{11}} = \square (type an exact answer, using radicals as ne

Explanation:

Step1: Combine radicals into one

$\sqrt{7x^9 \cdot 28x^{11}}$

Step2: Multiply coefficients and variables

$\sqrt{7 \cdot 28 \cdot x^{9+11}} = \sqrt{196x^{20}}$

Step3: Simplify the radical

$\sqrt{196x^{20}} = \sqrt{14^2 \cdot (x^{10})^2} = 14x^{10}$

Answer:

$14x^{10}$