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Question
c = (5)sin(35°) c = (5)cos(35°) c = 5 / sin(35°) c = 5 / cos(35°)
Step1: Recall sine - function definition
In a right - triangle, $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$. Here, $\theta = 35^{\circ}$, the opposite side to $\angle B$ is $b = 5$ inches and the hypotenuse is $c$. So, $\sin(35^{\circ})=\frac{5}{c}$.
Step2: Solve for $c$
Cross - multiply the equation $\sin(35^{\circ})=\frac{5}{c}$ to get $c\times\sin(35^{\circ}) = 5$, then $c=\frac{5}{\sin(35^{\circ})}$.
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$c=\frac{5}{\sin(35^{\circ})}$