Question

a single die is rolled twice. the 36 equally - likely outcomes are shown to the right.
find the probability of getting two numbers whose sum exceeds 16.
the probability of getting two numbers whose sum exceeds 16 is \square.
(type an integer or a simplified fraction.)

Explanation:

Step1: Determine possible die rolls

A die has numbers 1 - 6. When rolled twice, the maximum sum of two numbers is \(6 + 6=12\).

Step2: Check sum exceeding 16

Since the maximum sum is 12, which is less than 16, there are 0 favorable outcomes.

Step3: Calculate probability

Probability \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{0}{36} = 0\).

Answer:

\(0\)