Question

a single force of 60 n acts upon a 42-kg block. what is the magnitude of the acceleration of the block?
the magnitude of the acceleration of the block is $\boldsymbol{square}$ $m/s^2$

Explanation:

Step1: Recall Newton's second law

$F = ma$

Step2: Rearrange for acceleration

$a = \frac{F}{m}$

Step3: Substitute given values

$a = \frac{60}{42}$

Step4: Simplify the expression

$a = \frac{10}{7} \approx 1.43$

Answer:

$\frac{10}{7}$ or approximately $1.43$ $m/s^2$