Question

a snack - size bag of carrots has a mean weight of 1.75 ounces and a standard deviation of 0.1 ounce. kendra bought a snack - size bag of carrots to measure and found that it weighed 1.68 ounces. what is the z - score for the snack - size bag of carrots that kendra measured?
options: - 0.70, - 0.07, 0.07, 0.70

Explanation:

Step1: Recall z-score formula

The z-score formula is $z = \frac{x - \mu}{\sigma}$, where $x$ is the measured value, $\mu$ is the population mean, and $\sigma$ is the population standard deviation.

Step2: Identify given values

$x = 1.68$, $\mu = 1.75$, $\sigma = 0.1$

Step3: Substitute values into formula

$z = \frac{1.68 - 1.75}{0.1}$

Step4: Calculate numerator first

$1.68 - 1.75 = -0.07$

Step5: Compute final z-score

$z = \frac{-0.07}{0.1} = -0.70$

Answer:

-0.70 (Option: -0.70)