Question

1. sodium nitride

a) $nano_3$
b) $nan$
c) $nan_3$
d) $na_3n$

1. iron(ii) oxide

a) $feo$
b) $feo_2$
c) $fe_2o$
d) $fe_2o_2$

1. $caco_3$

a) calcium monocarbon trioxide
b) calcium carbide
c) calcium carbonite
d) calcium carbonate

1. $albr_3$

a) aluminum bromide
b) aluminum tribromide
c) aluminum bromine
d) monoaluminum tribromide

1. $ba_3(po_4)_2$

a) tribarium diphosphate
b) barium diphosphate
c) barium phosphate
d) barium phosphide

1. $fe(no_3)_2$

a) iron nitrate
b) iron dinitrate
c) iron(ii) nitrate
d) iron(i) nitrate

1. what is the name of $ca(no_3)_2$

a) calcium nitrite
b) calcium ii nitrate
c) calcium nitrate
d) carbon nitrate

Explanation:

Step1: Solve Q7: Sodium nitride

Sodium ($\text{Na}^+$) has +1 charge, nitride ($\text{N}^{3-}$) has -3 charge. Balance charges: $3\text{Na}^+ + \text{N}^{3-}
ightarrow \text{Na}_3\text{N}$

Step2: Solve Q8: Iron(II) oxide

Iron(II) ($\text{Fe}^{2+}$) has +2 charge, oxide ($\text{O}^{2-}$) has -2 charge. Balance charges: $\text{Fe}^{2+} + \text{O}^{2-}
ightarrow \text{FeO}$

Step3: Solve Q9: $\text{CaCO}_3$

$\text{Ca}^{2+}$ is calcium, $\text{CO}_3^{2-}$ is carbonate ion. Combine to name: calcium carbonate

Step4: Solve Q10: $\text{AlBr}_3$

$\text{Al}^{3+}$ is aluminum, $\text{Br}^-$ is bromide. For group 13 metals, we omit prefixes: aluminum bromide

Step5: Solve Q11: $\text{Ba}_3(\text{PO}_4)_2$

$\text{Ba}^{2+}$ is barium, $\text{PO}_4^{3-}$ is phosphate ion. Balance charges give the formula, name is barium phosphate

Step6: Solve Q12: $\text{Fe(NO}_3\text{)}_2$

$\text{NO}_3^-$ is nitrate, $\text{Fe}^{2+}$ (from 2 nitrate ions balancing charge) is iron(II): iron(II) nitrate

Step7: Solve Q13: $\text{Ca(NO}_3\text{)}_2$

$\text{Ca}^{2+}$ is calcium, $\text{NO}_3^-$ is nitrate. Calcium has only +2 charge, so name is calcium nitrate

Answer:

1. d) $\text{Na}_3\text{N}$
2. a) $\text{FeO}$
3. d) calcium carbonate
4. a) aluminum bromide
5. c) barium phosphate
6. c) iron(II) nitrate
7. c) calcium nitrate