Question

solid iron reacts with aqueous copper(ii) sulfate (cuso₄) to produce solid copper and aqueous iron(ii) sulfate (feso₄). write a balanced chemical equation for this reaction.

Explanation:

Step1: Write the reactants and products

The reactants are solid iron (Fe) and aqueous copper(II) sulfate ($CuSO_4$), and the products are solid copper (Cu) and aqueous iron(II) sulfate ($FeSO_4$). So the un - balanced equation is $Fe(s)+CuSO_4(aq)
ightarrow Cu(s)+FeSO_4(aq)$.

Step2: Check the balance of elements

On the left - hand side, we have 1 Fe atom, 1 Cu atom, 1 S atom, and 4 O atoms. On the right - hand side, we have 1 Fe atom, 1 Cu atom, 1 S atom, and 4 O atoms. The equation is already balanced.

Answer:

$Fe(s)+CuSO_4(aq)
ightarrow Cu(s)+FeSO_4(aq)$