Question

2 $\begin{cases} 6x + 5y = 15 \\ -6x - 10y = 0 end{cases}LXB0y=-3LXB16x + 5(-3)=15LXB2+15 +15LXB3x=5$solution: $\boldsymbol{5, -3}$4 $\begin{cases} 5x - 2y = 22 \\ 8x - 2y = 28 end{cases}$solution: ____

Explanation:

Step1: Subtract the two equations

$$(8x - 2y) - (5x - 2y) = 28 - 22$$
$$8x - 2y - 5x + 2y = 6$$
$$3x = 6$$

Step2: Solve for $x$

$$x = \frac{6}{3} = 2$$

Step3: Substitute $x=2$ into first equation

$$5(2) - 2y = 22$$
$$10 - 2y = 22$$

Step4: Solve for $y$

$$-2y = 22 - 10$$
$$-2y = 12$$
$$y = \frac{12}{-2} = -6$$

Answer:

$2, -6$