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solve for d. -2(2d - 19) ≤ 4 + 2d - 8 write your answer using a decimal…

Question

solve for d.
-2(2d - 19) ≤ 4 + 2d - 8
write your answer using a decimal, whole number, or fraction in lowest terms.

Explanation:

Step1: Expand the left - hand side

$-2(2d - 19)=-4d + 38$, so the inequality becomes $-4d + 38\leq4 + 2d-8$.

Step2: Simplify the right - hand side

$4 + 2d-8=2d - 4$, so we have $-4d + 38\leq2d - 4$.

Step3: Add $4d$ to both sides

$-4d+4d + 38\leq2d+4d - 4$, which simplifies to $38\leq6d - 4$.

Step4: Add 4 to both sides

$38 + 4\leq6d-4 + 4$, resulting in $42\leq6d$.

Step5: Divide both sides by 6

$\frac{42}{6}\leq\frac{6d}{6}$, so $7\leq d$.

Answer:

$d\geq7$