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solve for a. -3a - 1 > 8 or a + 20 > 19 write your answer as a compound…

Question

solve for a. -3a - 1 > 8 or a + 20 > 19 write your answer as a compound inequality with integers.

Explanation:

Step1: Solve \(-3a - 1 > 8\)

Add 1 to both sides: \(-3a - 1 + 1 > 8 + 1\)
Simplify: \(-3a > 9\)
Divide both sides by -3 (remember to reverse the inequality sign): \(\frac{-3a}{-3} < \frac{9}{-3}\)
Simplify: \(a < -3\)

Step2: Solve \(a + 20 > 19\)

Subtract 20 from both sides: \(a + 20 - 20 > 19 - 20\)
Simplify: \(a > -1\)

Answer:

\(a < -3\) or \(a > -1\)