Question

solve for h. -8h + 10 < -11h - 19 + 2 write your answer with h first, followed by an inequality symbol.

Explanation:

Step1: Simplify the right - hand side

First, simplify the right - hand side of the inequality $-11h - 19+2$.
$-11h-19 + 2=-11h-17$.
So the inequality becomes $-8h + 10<-11h-17$.

Step2: Add $11h$ to both sides

Adding $11h$ to both sides helps to get all $h$ terms on one side.
$(-8h+11h)+10<(-11h + 11h)-17$.
$3h+10<-17$.

Step3: Subtract 10 from both sides

Subtract 10 from both sides to isolate the term with $h$.
$3h+10 - 10<-17-10$.
$3h<-27$.

Step4: Divide both sides by 3

Divide both sides of the inequality by 3 to solve for $h$.
$\frac{3h}{3}<\frac{-27}{3}$.
$h < - 9$.

Answer:

$h<-9$